We study the two-observer disagreement $\mathbb{E}\,|S_A - S_B|$ in Akers–Engelhardt–Harlow–Penington–Vardhan non-isometric holographic codes, with observers included via the Harlow–Usatyuk–Zhao cloning rule. Our headline result is an entropy-replacement theorem: the full, $V$-dependent von Neumann disagreement between two observers is governed, at leading order, by the classical Shannon disagreement of the bulk-marginal diagonals, $\big[S(\rho_{R_A}) - S(\rho_{R_B})\big] - \big[H(P_A) - H(P_B)\big] = O_{L^2}\!\big(d^{-2} d_M^{-1}\big)$, where $P_X$ is the diagonal of the bulk $X$-marginal in the cloning basis. This closes the gap left by earlier versions, which computed only the diagonal (no-$V$) model and left open whether it governed the true observer entropy.
With the replacement in hand we obtain two scaling laws. For Haar-random bulk states the disagreement law is unconditional, $\mathbb{E}|S_A - S_B| \to \sqrt{2/\pi}\,/(d_M\, d_B^{3/2})$; for random product bulk states it is $\mathbb{E}|S_A - S_B| \to \sqrt{4(\pi^2/3-3)/\pi}\, d_B^{-1/2}$, conditional on the product-class replacement principle. The exponent gap between the two classes is exactly $1$. The Haar law is proved theorem-grade with no numerical constant inside the proof: the diagonal-to-bulk error is reduced, by a centered-operator identity, to the same base moment that controls the off-diagonal error. We verify the structural identity, the replacement bound, and both scalings against full-simulation data, including out-of-sample tests at sub-$\sigma$ precision.